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(H)=-16H^2+576H
We move all terms to the left:
(H)-(-16H^2+576H)=0
We get rid of parentheses
16H^2-576H+H=0
We add all the numbers together, and all the variables
16H^2-575H=0
a = 16; b = -575; c = 0;
Δ = b2-4ac
Δ = -5752-4·16·0
Δ = 330625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{330625}=575$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-575)-575}{2*16}=\frac{0}{32} =0 $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-575)+575}{2*16}=\frac{1150}{32} =35+15/16 $
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